Which digit is not in 2 29?

2^29 leaves a remainder of 5 when divided by 9. The sum of all the digits from 1 to 9 is evenly divisible by 9. Therefore the missing number is 4.

What two digit number has exactly $9$ Factors?

Since factors come in pairs, the only way to have an odd number of factors is to have two factors be the same. In other words, to be a square number. There aren’t too many 2 digit square numbers, so lets just take it from the top. Working backwards, the largest 2 digit number with exactly 9 factors is 36.

What does the digit 9 represent?

When alone, each number (or digit) is in the ones place. That means its value is simply the digit itself. For example, 9 stands for 9 ones, and 4 stands for 4 ones.

What is a doubles fact for 3 4?

For example, 3 + 4 is a near double as it is just a single digit away from the doubles fact 3 + 3. 10. Near doubles draw on a core understanding of doubles facts, you then add or subtract one to get a final number. 11.

How many possible five digit numbers are there between 0-9?

Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number. Out of these, 104 start with zero (once we start with 0, there are only 4 slots to fill, where we have 10 choices each). So, the number of possible five digit numbers is. 105 − 104 = 9 × 104 = 90000. These are the numbers 10000 to 99999.

How often is the digit 10 a 2?

In fact, any digit is a 2 roughly one tenth of the time. We say “roughly” because there are (very common) boundary conditions. For example, between 1 and 100, the 10’s digit is a 2 exactly 1/10 th of the time.

How do you find a nine digit number?

Find a nine digit numbers, using the numbers 1 to 9, and using each number once without repeats, such that; the first digit is a number divisible by 1. The first two digits form a number divisible by 2; the first three digits form a number divisible by 3 and so on until we get a nine digit number divisible by 9.

How many 2s are there in the third digit of 63525?

We can apply almost the exact same logic to see that there are the same number of 2s in the 3rd digit in the range 0 – 63525 as there as in the range 0 – 70000. So, rather than rounding down, we round up. The final case may be the trickiest, but it follows from the earlier logic. Consider x = 62523 and d = 3.