Table of Contents

## Which digit is not in 2 29?

2^29 leaves a remainder of 5 when divided by 9. The sum of all the digits from 1 to 9 is evenly divisible by 9. Therefore the missing number is 4.

### What two digit number has exactly $9$ Factors?

Since factors come in pairs, the only way to have an odd number of factors is to have two factors be the same. In other words, to be a square number. There aren’t too many 2 digit square numbers, so lets just take it from the top. Working backwards, the largest 2 digit number with exactly 9 factors is 36.

**What does the digit 9 represent?**

When alone, each number (or digit) is in the ones place. That means its value is simply the digit itself. For example, 9 stands for 9 ones, and 4 stands for 4 ones.

**What is a doubles fact for 3 4?**

For example, 3 + 4 is a near double as it is just a single digit away from the doubles fact 3 + 3. 10. Near doubles draw on a core understanding of doubles facts, you then add or subtract one to get a final number. 11.

## How many possible five digit numbers are there between 0-9?

Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number. Out of these, 104 start with zero (once we start with 0, there are only 4 slots to fill, where we have 10 choices each). So, the number of possible five digit numbers is. 105 − 104 = 9 × 104 = 90000. These are the numbers 10000 to 99999.

### How often is the digit 10 a 2?

In fact, any digit is a 2 roughly one tenth of the time. We say “roughly” because there are (very common) boundary conditions. For example, between 1 and 100, the 10’s digit is a 2 exactly 1/10 th of the time.

**How do you find a nine digit number?**

Find a nine digit numbers, using the numbers 1 to 9, and using each number once without repeats, such that; the first digit is a number divisible by 1. The first two digits form a number divisible by 2; the first three digits form a number divisible by 3 and so on until we get a nine digit number divisible by 9.

**How many 2s are there in the third digit of 63525?**

We can apply almost the exact same logic to see that there are the same number of 2s in the 3rd digit in the range 0 – 63525 as there as in the range 0 – 70000. So, rather than rounding down, we round up. The final case may be the trickiest, but it follows from the earlier logic. Consider x = 62523 and d = 3.